NBHM

SCHOLARSHIPS FOR PURSUING DOCTORAL PROGRAMME
(Ph. D) IN MATHEMATICS .

भारत सरकार/GOVERNMENT OF INDIA
राष्ट्रीय उच्चतर गणित बोर्ड / NATIONAL BOARD FOR HIGHER MATHEMATICS
(परमाणु ऊर्जा विभाग/ Department of Atomic Energy)
पहली मंजिल, ओ वाय सी बिल्डिंग, छ. शि. म. मार्ग, मुंबई - 400 001/
1st Floor, OYC Building, CSM Marg, Mumbai - 400 001
Gram: ATOMERG/ टेलीफोन नं./Phone: 022-22286 2568/2569
फैक्स नं./ Fax: 022-22028972/22048476

12/11/2023

दिवाली आशा, विश्वास और जीत का त्योहार है। यह दिवाली आपको अपने सपनों और जुनून को पूरा करने के लिए प्रेरित करे। आपको अपने शिक्षकों और गुरुओं का मार्गदर्शन और समर्थन हमेशा मिलता रहे। आप अपनी उपलब्धियों से अपने माता-पिता और दोस्तों को गौरवान्वित महसूस कराएं। आपको और सभी विद्यार्थियों को दीपावली की शुभकामनाएँ!

29/08/2023
30/07/2023

Do you love mathematics and want to solve challenging problems? Do you aspire to become a Junior Research Fellow (JRF) in mathematics and pursue a research career? Do you want to learn from the experts and join a vibrant community of math enthusiasts?

If yes, then you should check out Quora, the best platform to ask questions and get answers from people who have the knowledge and experience you need. Quora is a place where you can find helpful tips, tricks, strategies and resources for preparing for the JRF exam in mathematics. You can also interact with other math lovers, share your doubts, insights and solutions, and learn from their feedback.

Quora is more than just a question-and-answer site. It is a community of learners who are passionate about mathematics and want to help each other grow. Whether you are a beginner or an expert, you will find something valuable and interesting on Quora.

So what are you waiting for? Join Quora today and start your journey towards becoming a JRF in mathematics. Click the link below and sign up for free. You won't regret it!
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22/07/2023

JRF STUDY 21/07/2023

learn KEY NOTES join now.

JRF STUDY In this **Quora **space, You can also ask me any doubts or queries related to

21/07/2023

20/07/2023

20/07/2023

20/07/2023

The function f(x) is bounded due to its continuity on the compact interval [0, 1]. This is a valid conclusion from the fact that f is continuous and f(x) = f(x + 1) for all x ∈ ℝ, which implies the periodicity of the function with a period of 1.
[IIT JAM 2021]

20/07/2023

a function is periodic with period 1 if its values repeat every 1 unit along the x-axis. This means that the function's behavior within any 1-unit interval is the same as in any other 1-unit interval[IIT JAM 2021]

20/07/2023

Let f : ℝ → ℝ be a continuous function satisfying f(x) = f(x+1) for all x ∈ ℝ. Then
A. f is bounded.
SOL. Let f : ℝ → ℝ be a continuous function satisfying f(x) = f(x+1) for all x ∈ ℝ.

The periodicity of f tells us that the image of f is f([0, 1]) . Since f is continuous and [0, 1] compact, it is bounded.
[ IIT JAM 2021]

17/07/2023

What does the partition function p(n) count?
a. Number of non-isomorphic groups
b. Number of non-cyclic groups
c. Number of possible partitions of n into positive integers
d. Number of elements in a cyclic group

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